int x = 3; void create() { write(x + "\\n"); }the driver would translate it into the following internal form before compiling the object:
int x; __INIT() { x = 3; } void create() { write(x + "\\n"); }If you add a function named __INIT() to one of your objects, then the driver will call it at object-load-time just as if the driver had inserted the function on its own. Be aware that if you do this and the driver needs to add __INIT in order to initialize variables, then there will be a conflict.